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x^2+336x-864=0
a = 1; b = 336; c = -864;
Δ = b2-4ac
Δ = 3362-4·1·(-864)
Δ = 116352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{116352}=\sqrt{576*202}=\sqrt{576}*\sqrt{202}=24\sqrt{202}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(336)-24\sqrt{202}}{2*1}=\frac{-336-24\sqrt{202}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(336)+24\sqrt{202}}{2*1}=\frac{-336+24\sqrt{202}}{2} $
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